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7x^2-75x-108=0
a = 7; b = -75; c = -108;
Δ = b2-4ac
Δ = -752-4·7·(-108)
Δ = 8649
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{8649}=93$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-75)-93}{2*7}=\frac{-18}{14} =-1+2/7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-75)+93}{2*7}=\frac{168}{14} =12 $
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